Suppose a dart is thrown at a target and the distance, X, from the bulls-eye is a random variable with pdf (Rayleigh Distribution):,f(x)=xe^((-x^2)/2) when x>=0 and 0 otherwise. The mean is sqrt(2Pi)/2. Now find the median, m, the value s.t. P(x<,)= P(x>m) = 0.5
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